Calculus

Please help me calculate these integrals.
Suppose that Int 0->1 f(t)dt=11 . Calculate each of the following.
A. int0->0.25 f(4t)dt=

B. int0->0.25 f(1−4t)dt=

C. int0.25->0.375 f(3−8t)dt=

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  1. Try substitution:
    u=4t
    du=4dt, or
    dt=(1/4)du
    then
    ∫f(4t)dt [0,0.25]
    =∫f(u)(1/4)du [0,4*0.25]
    =(1/4)∫f(u)du [0,1]
    =(1/4)*11
    =11/4

    The other problems should work similarly.

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