Calculus

Can someone please tell me how to find the following integral?

cos^4(2q)*sin(2q) dq

  1. 👍 0
  2. 👎 0
  3. 👁 107
  1. If z=cos(2q) then dz=-2sin(2q)dq.
    Integral=-1/2*Integral z^4dz=
    -1/10*z^5+C

    1. 👍 0
    2. 👎 0

Respond to this Question

First Name

Your Response

Similar Questions

  1. Math Help Please

    What are the ratios for sin A and cos A? The diagram is not drawn to scale. Triangle Description- AB = 29 AC = 20 BC - 21 A. sin A = 20/29, cos A = 21/29 B. sin A = 21/29, cos A = 20/21 C. sin A = 21/29, cos A = 20/29****? D. sin

    asked by Battia Anne on June 7, 2016
  2. calculus

    Find complete length of curve r=a sin^3(theta/3). I have gone thus- (theta written as t) r^2= a^2 sin^6 t/3 and (dr/dt)^2=a^2 sin^4(t/3)cos^2(t/3) s=Int Sqrt[a^2 sin^6 t/3+a^2 sin^4(t/3)cos^2(t/3)]dt =a Int

    asked by ms on September 18, 2013
  3. Trig

    Find sin(s+t) and (s-t) if cos(s)= 1/5 and sin(t) = 3/5 and s and t are in quadrant 1. =Sin(s)cos(t) + Cos(s)Sin(t) =Sin(1/5)Cos(3/5) + Cos(-1/5)Sin(3/5) = 0.389418 Sin(s-t) =sin(s)cos(t) - cos(s)sin(t) =sin(-3/5)cos(1/5) -

    asked by Sally on May 7, 2015
  4. calculus

    Find the points on the curve y= (cos x)/(2 + sin x) at which the tangent is horizontal. I am not sure, but would I find the derivative first: y'= [(2 + sin x)(-sin x) - (cos x)(cos x)]/(2 + sin x)^2 But then I don't know what to

    asked by CMM on October 24, 2010
  5. Calculus 12th grade (double check my work please)

    1.)Find dy/dx when y= Ln (sinh 2x) my answer >> 2coth 2x. 2.)Find dy/dx when sinh 3y=cos 2x A.-2 sin 2x B.-2 sin 2x / sinh 3y C.-2/3tan (2x/3y) D.-2sin2x / 3 cosh 3yz...>> my answer. 2).Find the derivative of y=cos(x^2) with

    asked by anon on March 6, 2011
  1. TRIG!

    Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6 x=1 - (3/4)sin^2 2x work on one side only! Responses Trig please help! - Reiny, Monday, February 23, 2009 at 4:27pm LS looks like the sum of cubes sin^6 x +

    asked by hayden on February 23, 2009
  2. Calculus AP

    Evaluate the integral interval from [0 to pi] t sin(3t)dt Use integration by parts u=t and dv=sin(3t)dt. then du=dt and v=-cos(3t)/3 here is my problem but Im having problem to solve with pi. ∫t sin(3t)dt = -tcos(3t)/3 -

    asked by Vicky on July 26, 2012
  3. triggggg help

    Let cos 67.5° = [√(2(+√2)]/2, find tan 67.5°. Show work and simplify. I'm not too sure if i'm doing this correct. I know that the given is cos 67.5° = [√(2(+√2)]/2 sin^2 x + cos^2 x = 1 x=67.5° sin^2 67.5° + cos^2

    asked by Jane on January 28, 2016
  4. Calculus

    I have two questions, because I'm preparing for a math test on monday. 1. Use the fundamental theorem of calculus to find the derivative: (d/dt) the integral over [0, cos t] of (3/5-(u^2))du I have a feeling I will be able to find

    asked by Jennifer on May 9, 2009
  5. Maths

    Question : Integrate [x/(1+(sin a*sin x))] from 0 to pi My first thought was to apply integrate f(x) dx= f(a-x) dx method Which simplified the integral into; 2I = integrate [pi/(1+(sin a*sin x))] dx , cancelling out x Then I made

    asked by Ashley on March 18, 2019
  6. calculus

    find max, min and saddle points of the give function f(x,y)=sin(x)+sin(y)+sin(x+y) 0

    asked by Help Please on March 9, 2012

You can view more similar questions or ask a new question.