A car starts from rest and accelerates uniformly along a straight horizontal road at 3 metres second squeared for 4 seconds.CALCULATE THE MAGNITUDE OF THE MAXIMUM VELOCITY OF THE CAR,I.E THE VELOCITY OF THE CAR AFTER ACCELERATING FOR 4 SECONDS.PLEASE SHOW ALL CALCULATIONS
V = at = 3m/s^2 * 4s = 12m/s.
To calculate the magnitude of the maximum velocity of the car, we can use the equation of motion:
v = u + at
Where:
v is the final velocity (magnitude of the maximum velocity)
u is the initial velocity (which is 0 in this case as the car starts from rest)
a is the acceleration (3 m/s^2)
t is the time taken (4 seconds)
Substituting the values into the equation:
v = 0 + (3 m/s^2)(4 s)
v = 0 + 12 m/s
v = 12 m/s
Therefore, the magnitude of the maximum velocity of the car is 12 m/s.