A car starts from rest and accelerates uniformly along a straight horizontal road at 3 metres second squeared for 4 seconds,after which it continues with a constant velocity for a further 6 seconds.CALCULATE THE MAGNITUDE OF THE MAXIMUM VELOCITY OF THE CAR, THAT IS THE VELOCITY OF THE CAR AFTER ACCELERATING FOR 4 SECONDS

V = at = 3m/s^2 * 4s = 12m/s.

To calculate the magnitude of the maximum velocity of the car, we need to break down the problem into two parts: the acceleration phase and the constant velocity phase.

1. Acceleration phase (0 to 4 seconds):
The car starts from rest, so the initial velocity (u) is 0 m/s. The car accelerates uniformly at a rate of 3 m/s^2 for 4 seconds. We can use the following kinematic equation to find the final velocity (v) during this phase:

v = u + at

Where:
v = final velocity
u = initial velocity
a = acceleration
t = time

Plugging in the values, we have:
v = 0 + (3 m/s^2)(4 s)
v = 12 m/s

2. Constant velocity phase (4 to 10 seconds):
After accelerating for 4 seconds, the car continues with a constant velocity for another 6 seconds. This means that the velocity remains the same during this phase. Therefore, the final velocity (v) of 12 m/s is also the maximum velocity of the car.

Hence, the magnitude of the maximum velocity of the car is 12 m/s.