math

Simplify by referring to the appropriate triangle or trigonometric identity:

cos(arctan(x))

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  1. sketch a right-angled triangle with some angle Ø
    , label the opposite side x and the adjacent side 1
    (this way tanØ = x/1 , and Ø = arctan(x/1)
    the hypotenuse would be √(x^2 + 1)
    and
    cosØ = 1/√(x^2+1)

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