What is the pH and pOH a solution that was made by adding 400 mL of water to 350 mL of 5.0 x 10^-3 M NaOH solution?

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  1. This is just a dilution problem.
    5E-3M NaOH x [(350)/(350+400)] OR
    use the dilution formula of
    mL1 x M1 = mL2 x M2

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