Pre-Calculas

I a lighthouse is 75 feet tall and boat is out at sea 40 min away, how far is the boaat from the lighthouse. I'm stump on this problem..Help!

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  1. By simple trigonometry on a plane:
    θ=48 minutes (angle of depression)
    h=75'
    distance = 75/tan(48')
    =75/0.01396
    =5371.1 feet away
    =1.02 mile approx.

    If you are looking for correction for the curvature of the earth, a more complex calculation will be required.

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