Temperature fell 28 degree at 6AM to 17 degree at 11AM. What's the equation ?
Do you mean fell FROM 28 degrees?
NO, it fell 28 degree from 6AM to 17 degree at 11AM.
temp=slope*time +b
slope= 17-28 /5hrs= -11/5
temp= -11/5 * (time-6am)+ b
put in the 6Am temp, and time to solve for b, and you have it.
To find the equation for the temperature change, we need to calculate the difference between the initial and final temperatures and determine the rate of change.
The initial temperature is given as 28 degrees at 6 AM, and the final temperature is 17 degrees at 11 AM.
To find the difference in temperature, we subtract the initial temperature from the final temperature:
17 degrees - 28 degrees = -11 degrees
The negative sign indicates that the temperature decreased.
Next, we need to determine the time interval between the initial and final temperatures. The initial temperature is at 6 AM, and the final temperature is at 11 AM.
The time difference is:
11 AM - 6 AM = 5 hours
Now we can find the rate of change (the slope) by dividing the change in temperature by the time interval:
Change in temperature / Time interval = Rate of change
-11 degrees / 5 hours = -2.2 degrees per hour
So, the equation for the temperature change is:
T(t) = -2.2t + 28
where T(t) is the temperature at time t in hours since 6 AM.