The melting of 0.140 g of Br2 (which occurs at -7.2 C at 1 atm pressure) absorbs 9.43 J of heat. Compute the enthalpy change in 2.00 mol of Br2 when it freezes.

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  1. Convert 2.00 mol Br2 to grams.
    moles = grams/molar mass.

    9.43 J x (? g Br2/0.140 g Br2) = xx J.

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