If you were going to graph this function what would be the coordinates of the points that you would plot? Is this a linear or nonlinear function? Explain.

f(x)= 2x+5 inputs (5) and (8)
f(8)= 2(8)+5=16+5=21
f(5)= 2(5)+5=10+5=15

Would the points be (5,15) and (8,21)?

Since X is of the 1st degree, this is a linear Eq. Therefore, your graph will be a st. line.

Smaller numbers are more convenient for graphing:

(-2,1), (2,9), (0,5).

Yes, the points would be (5,15) and (8,21). To find these points, you substitute the given x-values into the function f(x) and calculate the corresponding y-values.

For the first point (5,15):
Substitute x = 5 into f(x): f(5) = 2(5) + 5 = 10 + 5 = 15. So, the y-value or output is 15.

For the second point (8,21):
Substitute x = 8 into f(x): f(8) = 2(8) + 5 = 16 + 5 = 21. So, the y-value or output is 21.

Hence, the coordinates of the points to plot on the graph are (5,15) and (8,21).

This function f(x) = 2x + 5 is a linear function because it can be expressed in the form y = mx + c, where m is the slope (in this case, 2) and c is the y-intercept (in this case, 5).