Trig

assume A= alpha
using complementary rule how do I solve for alpha?

cos(2A+40) =sin(3A-60)

I don't understand how to start the question. What are the steps in solving for alpha.

Do i get cos to equal sin somehow?

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  1. for the complementary angle property
    sinA = cos(90-A)

    so

    cos(2A+40) = sin(3A-60)
    sin(90 - (2A+40) ) = sin(3A-60)
    sin(50-2A) = sin(3A-60)
    then
    50-2A = 3A-60
    110 = 5A
    A = 22°

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