How many grams of bromine liquid are needed to make 6 moles of KBr?
Br2(l) ==> 2KBr(s)
6 moles KBr x (1 mole Br2/2 moles KBr) = moles Br2
Then moles = grams/molar mass.
Substitute and solve for grams.
6 moles KBr x (1 mole Br2/2 moles KBr) = moles Br2
Then moles = grams/molar mass.
Substitute and solve for grams.