In a region containing a uniform electric field at right angle to the magnetic field suppose, for instance, that Vector B point in X direction and Vector E in the Z axis as shown below. What path will a particle that is released from the origin it follow. (Describe the trajectory movement by a diagram)
In order to determine the trajectory of a particle released in a region with a uniform electric field at right angles to a magnetic field, we need to consider the Lorentz force experienced by the particle.
The Lorentz force is given by the equation:
F = q(E + v x B),
where F is the force experienced by the particle, q is the charge of the particle, E is the electric field, v is the velocity of the particle, and B is the magnetic field.
In this case, the electric field (E) is in the Z-axis direction and the magnetic field (B) is in the X-axis direction at right angles to each other.
When a particle is released from the origin, it will experience a force due to both the electric and magnetic fields. The force will be perpendicular to both the electric and magnetic fields.
Considering the given directions of the electric and magnetic fields (E in the Z-axis and B in the X-axis), the force experienced by the particle will be in the Y-axis direction.
Therefore, the particle released from the origin will follow a curved path perpendicular to both the electric and magnetic fields, as shown below:
```
|
\
\ Path of the particle
\
\_____
|
+Origin
```
This path is a result of the combination of the electric and magnetic fields acting on the charged particle, causing it to move in a circular or helical trajectory.