I will be very greatfull to you,if you help me to balance the below equations:
1.)NaOH+S gives rise to Na2S+S2O3+H2O
2.)Al(OH)3+3HCL gives rise to AlCl3+3H2O
Al(OH)3 + 3HCl ==> AlCl3 + 3H2O is already balanced.
I think you may have made a typo in the first one. I suspect it is S2O3^2- on the right which is the way I will balance it.
6NaOH + 4S ==> 2Na2S + Na2S2O3 + 3H2O
If you did not make a typo and it really is s2O3, then it is balanced as follows:
6NaOH + 5S ==> 3Na2S + S2O3 + 3H2O
Sure, I can help you balance these chemical equations. Balancing equations involves making sure there is an equal number of atoms on both sides of the equation.
1.) NaOH + S → Na2S + S2O3 + H2O
To balance this equation, we start by counting the number of atoms on each side.
On the left side:
1 Na, 1 O, 1 H, 1 S
On the right side:
2 Na, 1 S, 3 O, 1 H
To balance the equation, we need to adjust the coefficients of the compounds. Let's go step by step.
Start by balancing the sodium (Na) atoms:
1 NaOH + S → 2 Na2S + S2O3 + H2O
Next, balance the sulfur (S) atoms:
1 NaOH + 1 S → 2 Na2S + 1 S2O3 + H2O
Now, balance the oxygen (O) atoms:
1 NaOH + 1 S → 2 Na2S + 3 S2O3 + H2O
Lastly, balance the hydrogen (H) atoms:
1 NaOH + 1 S → 2 Na2S + 3 S2O3 + 2 H2O
The balanced equation is:
NaOH + S → 2 Na2S + 3 S2O3 + 2 H2O