there are 80 students enrolled in statistics. (a)you and 11 other earned the same score. what percent of the class received your score? (b)forty percent of the class received a grade of C. how many students received a C? (c) only 7.5% of the class received a D. how many students is this? A student claims that .5% of the class failed. why is this impossible?
a) 11 + 1 (you) = 12. 12/80 = 0.15 = 15%
b)40% = 0.4, 0.4 x 80 = 32.
c) 7.5% = 0.075, 0.075 x 80 = 6
Also, 0.5% x 80 = 0.005 x 80 = 0.4 students, which doesn't make sense.
fill in missing proportion for normal distribution.
1. .40
2. .10
72%
If the class inclues you ... then how can it be a pool of 80 ? the pool would have to be 79 and only 11 students got your score ?
To answer these questions, we'll use some basic math concepts and formulas. Let's go step by step:
(a) To find the percentage of the class that received your score, you need to know the total number of students who earned the same score as you and divide it by the total class size. Then, multiply the result by 100 to get the percentage. So, the calculation would be:
Number of students who earned your score = you + 11 others = 1 + 11 = 12
Percentage = (Number of students who earned your score / Total class size) * 100
Plug in the values:
Percentage = (12 / 80) * 100
Now, you can calculate the percentage and find the answer.
(b) If 40% of the class received a grade of C, you need to find the number of students that corresponds to this percentage. To do that, multiply 40% by the total class size. The calculation would be:
Number of students who received a C = 40% * Total class size
Plug in the values:
Number of students who received a C = 0.40 * 80
Calculate the number of students who received a C to find the answer.
(c) Following the same principle, if only 7.5% of the class received a D, you can find the number of students using the formula:
Number of students who received a D = 7.5% * Total class size
Plug in the values and calculate the result.
As for the student's claim that 0.5% of the class failed, this claim is impossible. The reason is that all the percentages mentioned so far (from part a, b, and c) add up to 100%. If 0.5% of the class failed, then the percentages would exceed 100%, which is not possible as it represents more than the total number of students in the class.