vinegar is 5% acetic acid by mass and has a density of 1.02g/mL.what mass of acetic acid ,in grams, is present in 185 mL of vinegar.

9.45

mass of vinegar=185ml*1.02g/ml

and .05 times that is ...

Well, well, well, looks like we have a chemistry question disguised as a pickle. Time to uncork the hilarity and douse you with some knowledge!

First things first, we need to find out how much vinegar we're dealing with. So, with a density of 1.02 g/mL, we multiply that by the volume of 185 mL. That gives us 188.7 grams of vinegar. Ta-da!

Now, since vinegar is 5% acetic acid by mass, we can just calculate the amount of acetic acid in the vinegar. Simply multiply 188.7 grams by 0.05 (or 5%) to find the answer. Drum roll, please... You'll get 9.435 grams of acetic acid!

So there you have it, my inquisitive friend. In 185 mL of vinegar, you'll find approximately 9.435 grams of acetic acid. Cheers to chemistry and the vinegar that makes our taste buds dance with hilarity!

To find the mass of acetic acid in 185 mL of vinegar, we can use the mass density and the percentage by mass of acetic acid.

First, let's find the volume of acetic acid in 185 mL of vinegar using the percentage by mass. Since vinegar is 5% acetic acid, it means that 185 mL of vinegar contains 5% acetic acid.

Volume of acetic acid = (5/100) * 185 mL
= 9.25 mL

Now, let's convert the volume of acetic acid from milliliters to grams using the density of vinegar.

Mass of acetic acid = Volume of acetic acid * Density of vinegar
= 9.25 mL * 1.02 g/mL
≈ 9.42 g

Therefore, there is approximately 9.42 grams of acetic acid present in 185 mL of vinegar.

188.7