A SOLUTION OF Nacl IN H2O HAS 3.80G NACL IN 1LITRE SOLUTION,WHAT IS MOLARITY?
To find the molarity of a solution, we need to know the amount of solute (in moles) and the volume of the solution (in liters). In this case, we have 3.80 grams of NaCl in a 1-liter solution.
To determine the amount of NaCl in moles, we need to convert grams to moles using the molar mass of NaCl. The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl):
Na: 22.99 g/mol
Cl: 35.45 g/mol
Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol
Now, we can calculate the moles of NaCl present in the solution:
moles of NaCl = mass of NaCl / molar mass of NaCl
= 3.80 g / 58.44 g/mol
Next, we need to determine the volume of the solution in liters. Since we have 1 liter of solution, we can use this as the volume.
Finally, we can calculate the molarity of the NaCl solution using the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
Molarity of the NaCl solution = moles of NaCl / volume of solution in liters
Plug in the values we calculated:
Molarity of the NaCl solution = (3.80 g / 58.44 g/mol) / 1 L
Now, let's calculate the molarity:
Molarity of the NaCl solution = 0.065 mol / 1 L
Therefore, the molarity of the NaCl in the given solution is approximately 0.065 M.