The partial molar volumes of the CCl4 and benzene are 122cm3/mol and 98.0 cm3/mol, respectively in a solution in which mole fraction of chloroform is 0.2. Calculate the volume occupied by 2.5 moles of the solution.
Thank yOu.
You have both benzene and chloroform mentioned; however, I assume you intended to write benzene for chloroform OR chloroform for benzene. I will assume the former.
nCCl4 = 0.8 x 2.5
nbenzene = 0.2 x 2.5
Then total V = (nbenzene*98 + nCCl4*122).
Thank you very Much Dr.Bob222 for your help and answer. Really appreciate the timing and response.
To calculate the volume occupied by 2.5 moles of the solution, we first need to calculate the mole fractions of both components using the given mole fraction of chloroform.
Given:
Partial molar volume of CCl4 (V1) = 122 cm3/mol
Partial molar volume of benzene (V2) = 98.0 cm3/mol
Mole fraction of chloroform (X1) = 0.2
Mole fraction of benzene (X2) = 1 - X1 = 1 - 0.2 = 0.8
Number of moles of the solution (n) = 2.5
Now, we can calculate the volume occupied by 2.5 moles of the solution.
Step 1: Calculate the total moles of each compound in the solution:
n1 = X1 * n = 0.2 * 2.5 = 0.5 moles of CCl4
n2 = X2 * n = 0.8 * 2.5 = 2 moles of benzene
Step 2: Calculate the volume of each compound in the solution:
V1_solution = V1 * n1 = 122 cm3/mol * 0.5 mol = 61 cm3 of CCl4
V2_solution = V2 * n2 = 98.0 cm3/mol * 2 mol = 196 cm3 of benzene
Step 3: Calculate the total volume occupied by the solution:
Volume_solution = V1_solution + V2_solution
Volume_solution = 61 cm3 + 196 cm3 = 257 cm3
Therefore, the volume occupied by 2.5 moles of the solution is 257 cm3.
To calculate the volume occupied by the solution, we need to consider the volumes of both the CCl4 and benzene components.
Given:
Partial molar volume of CCl4 (V1) = 122 cm^3/mol
Partial molar volume of benzene (V2) = 98.0 cm^3/mol
Mole fraction of chloroform (χ1) = 0.2
Mole fraction of benzene (χ2) = 1 - χ1 = 1 - 0.2 = 0.8
Number of moles of the solution (n) = 2.5 mol
First, we need to calculate the total moles of CCl4 (n1) and benzene (n2) in the solution:
n1 = χ1 * n = 0.2 * 2.5 = 0.5 mol
n2 = χ2 * n = 0.8 * 2.5 = 2.0 mol
Next, we can calculate the volume occupied by CCl4 (V1sol) and benzene (V2sol) in the solution:
V1sol = n1 * V1 = 0.5 * 122 = 61 cm^3
V2sol = n2 * V2 = 2.0 * 98.0 = 196 cm^3
Finally, we can calculate the total volume occupied by the solution:
Total Volume (Vsol) = V1sol + V2sol = 61 + 196 = 257 cm^3
Therefore, 2.5 moles of the given solution occupies approximately 257 cm^3.