Two cars are traveling on a desert road, as shown below. After 5.0 s, they are side by side at the next telephone pole. The distance between the poles is 107 m.

(a) the displacement of car A after 5.0 s
1 m
(b) the displacement of car B after 5.0 s
2 m
(c) the average velocity of car A during 5.0 s
3 m/s
(d) the average velocity of car B during 5.0 s
4 m/s

To find the displacement of each car, we need to use their average velocities. The average velocity is calculated by dividing the displacement by the time it takes to cover that distance.

The given information tells us that after 5.0 seconds, the cars are side by side at the next telephone pole, which is 107 meters away.

(a) To find the displacement of car A after 5.0 seconds, we can assume that it covered half of the total distance since it is side by side with car B. So, the displacement of car A would be half of the distance between the poles.

Displacement of car A = (1/2) * 107 m = 53.5 m

Therefore, the displacement of car A after 5.0 seconds is 53.5 m.

(b) Similarly, the displacement of car B would also be half of the distance between the poles.

Displacement of car B = (1/2) * 107 m = 53.5 m

Therefore, the displacement of car B after 5.0 seconds is 53.5 m.

(c) The average velocity of car A during 5.0 seconds can be calculated by dividing the displacement of car A by the time (5.0 seconds).

Average velocity of car A = (Displacement of car A) / (Time) = 53.5 m / 5.0 s = 10.7 m/s

Therefore, the average velocity of car A during 5.0 seconds is 10.7 m/s.

(d) Similarly, the average velocity of car B during 5.0 seconds can be calculated using the displacement of car B and the time.

Average velocity of car B = (Displacement of car B) / (Time) = 53.5 m / 5.0 s = 10.7 m/s

Therefore, the average velocity of car B during 5.0 seconds is 10.7 m/s.