(0.75 moles Al(NO3)3/L Al(NO3)3) x 0.040 L Al(NO3)3 = ??moles Al(NO3)3
I am unsure how to find the factor to convert moles Al(NO3)3 into moles NO3.
i think that if i do the first section,
you get .03 moles as your answer for moles of Al(NO3)3, but I am not sure.
how can i convert the correct answer for moles Al(NO3)3 into moles NO3 ?
The question said to use dimensional analysis...
You want NO3^- so how many NO3^- are in 1 mole Al(NO3)3. Three? Then moles NO3^- =
??moles Al(NO3)3 x [3 moles NO3^-/1 mol Al(NO3)3]
Look how the units you don't want to keep cancel and the unit you want to keep stays.
oh ok thanks i got .09 i hope that's right
Yes and no. Some profs would count that as incorrect. Note there are two significant figures in 0.75 and 0.40; therefore, you are allowed two s.f. in the answer. The answer should be quoted as 0.090 and not 0.09 moles NO3^-.
To convert moles of Al(NO3)3 to moles of NO3, you need to consider the chemical formula and stoichiometry of the compound.
The chemical formula of Al(NO3)3 indicates that for every 1 mole of Al(NO3)3, there are 3 moles of NO3 ions. This is because the subscript 3 next to NO3 represents the number of NO3 ions in each formula unit of Al(NO3)3.
In this case, you have 0.75 moles of Al(NO3)3. To convert this to moles of NO3, you can use the stoichiometric ratio of 3 moles of NO3 per 1 mole of Al(NO3)3:
0.75 moles Al(NO3)3 x (3 moles NO3 / 1 mole Al(NO3)3) = 2.25 moles NO3
So, the correct answer is 2.25 moles of NO3.
To find this conversion factor, you need to refer to the balanced chemical equation or the chemical formula to determine the ratio of moles between the two species you are interested in.