solve 4^(3-x)=7 to 3 s.f. showing all workings.

I have got as far as -x =log(7)-3log4/log(4)

take log of both sides

log(4^(3-x)) = log 7
(3-x)log4 = log7
3-x = log7/log4
-x = -3 + log7/log4
x = 3 - log7/log4
= appr. 1.5963