3. Moving Costs

Moving company A charges $80 plus $55 an hour to move households across town. Moving Company B charges $75 an hour for cross-town moves. For what lengths of time is Moving Company B more expensive than Moving Company A? Write an inequality and solve for time t.

Show your work not just the final answer.

I am not inclined to show work for someone to copy.

costeach= costperhour*time + fixedcost
In one, the fixed cost is zero.

find time when both are equal (set the two cost equations equal to each other).
then, for times greater than that, Company B is costlier, and for times less than that, Company A is costlier.

Iam wanting help i do not want you to do it for me. I just needed it broken down in order to answer Thank you for your help.

A:

80 + 55 + 55 + 55 + 55

B:
75 + 75 + 75 + 75

Thank you for you answer Ms Sue.

To determine the lengths of time for which Moving Company B is more expensive than Moving Company A, we need to compare the costs of both companies and find the point at which Company B becomes more expensive.

Let's start by analyzing the charges of both companies:

Moving Company A charges a fixed fee of $80 plus an additional $55 per hour.
Moving Company B charges a flat rate of $75 per hour.

We need to find the time (t) for which the cost of Company B is greater than the cost of Company A.

For Company A, the cost can be expressed as:
Cost A = $80 + $55t

For Company B, the cost can be expressed as:
Cost B = $75t

To find the time (t) when Company B is more expensive than Company A, we need to set up an inequality and solve for t.

Cost B > Cost A

$75t > $80 + $55t

Next, we can solve this inequality step by step:

$75t - $55t > $80
$20t > $80
t > $80/$20
t > $4

Therefore, if the time (t) is greater than 4 hours, Moving Company B will be more expensive than Moving Company A. This means that for any length of time greater than 4 hours, Company B will have a higher cost than Company A.