1. The acceleration due to gravity calculated this way works well for objects near the Earth’s surface. How would you have to change the above equation if the object was 100,000 meters above the ground?

(Note: this question refers to Newton’s equation for the force of gravity between two objects. How would that change if the radius of the earth or distance were increased by 100,000 meters. To help you answer this question, please review your textbook, chapter 3, Newton’s law of Gravitation section.)

the force diminishes by the square of distance.

acceleration due to gravity= 9.8 (r/re)^2

re radius of earth
r is distance from center of Earth.

so what is the answer

To calculate the acceleration due to gravity for an object 100,000 meters above the ground, we need to consider Newton's law of gravitation. The equation is given by:

F = G * (m1 * m2) / r^2

Where:
F is the force of gravity between two objects,
G is the gravitational constant (approximately 6.674 x 10^-11 N*m^2/kg^2),
m1 and m2 are the masses of the two objects, and
r is the distance between the centers of the two objects.

In this case, we want to find the acceleration due to gravity, which can be defined as the force of gravity acting on an object of mass m. So we can rearrange the equation as follows:

F = m * g

Where:
m is the mass of the object, and
g is the acceleration due to gravity.

By equating the two equations, we can find the value of g:

m * g = G * (m1 * m2) / r^2

Now, let's substitute the variables with the corresponding values for an object 100,000 meters above the ground. The radius of the Earth (r) would need to be increased by 100,000 meters, so we would have:

r' = r + 100,000

Substituting this into the equation, we get:

m * g = G * (m1 * m2) / (r + 100,000)^2

This new equation takes into account the increased distance between the object and the Earth's surface and allows us to calculate the revised acceleration due to gravity.