A magnet is plunged into and out of a coil of wire 2 times per second. This induces 5 volts. If the number of coils in the wire is doubled from 100 to 200, and the original rate 2 times per second is kept the same, what will be the new voltage induced.
The voltage will double, since it is proportional to the number of coil windings.
305
no.of turns is directly proportional to v/t
therefore n1/n2=v1/v2*t2/t1
100/200=5/v2*2/2
v2=10
To calculate the new voltage induced, we need to understand the relationship between the number of coils in the wire and the voltage induced.
The voltage induced in a coil of wire is directly proportional to the rate of change of magnetic flux passing through the coil. The magnetic flux is a measure of the total magnetic field passing through the coil and depends on factors like the strength of the magnet and the number of magnetic field lines passing through the coil.
In this scenario, the original number of coils in the wire is 100, and when the magnet is plunged into and out of the coil 2 times per second, it induces 5 volts. This means that each cycle of the magnet induces a voltage of 2.5 volts (5 volts divided by 2 cycles).
If we double the number of coils to 200 while keeping the rate of 2 times per second the same, the new voltage induced can be calculated as follows:
The number of cycles per second remains the same, so the new voltage induced per cycle should remain the same. Since the number of coils is doubled, we can expect the total voltage induced to be doubled as well.
Therefore, the new voltage induced would be 2 times the original voltage, which is 2 * 2.5 volts = 5 volts.
Thus, the new voltage induced when the number of coils is doubled from 100 to 200, with a rate of 2 times per second, would be 5 volts.