A sports car moving at constant speed travels 120 m in 5.1 s. If it then brakes and comes to a stop in 4.0 s, what is its acceleration? Express the answer in terms of g's, where g = 9.80 m/s2. (Take the positive direction to be the direction of travel.)

Initial speed before braking = 120/5.1 = 23.53 m/s

Braking acceleration rate = 23.53 m/s/4.0 is (Vfinal -Vinitial)/(time)
= -5.88 m/s^2

Divide that by g = 9.81 m/s^2 for the number g's.

Well, let's calculate the acceleration of this sports car, shall we? First, we'll need to find the initial velocity of the car before braking.

To find the initial velocity, we can use the formula:

v = d/t

where v is the velocity, d is the distance traveled, and t is the time taken.

So, using the given values, we can plug them into the formula:

v = 120 m / 5.1 s = 23.529 m/s

Now that we have the initial velocity, we can find the acceleration using the formula:

a = (0 - v) / t

where a is the acceleration, v is the initial velocity, and t is the time taken to come to a stop.

Plugging in the values, we get:

a = (0 - 23.529 m/s) / 4.0 s = -5.88225 m/s^2

Now, to express the acceleration in terms of g's, we simply divide the acceleration by the acceleration due to gravity (g):

a_g = a / g = -5.88225 m/s^2 / 9.80 m/s^2 = -0.6 g

So, the acceleration of the sports car is approximately -0.6 g's.

Remember, it's all about stopping and going...sometimes it's just a matter of knowing when to hit the brakes!

To find the acceleration of the sports car, we first need to calculate its initial velocity and final velocity.

Given:
Displacement (d) = 120 m
Time (t) = 5.1 s (for constant speed)
Time (t) = 4.0 s (to come to a stop)
Acceleration due to gravity (g) = 9.80 m/s^2

Step 1: Calculate the initial velocity (v0) for constant speed.
Since the car is moving at a constant speed, the initial velocity (v0) is the same as the final velocity (v). We can find the initial velocity using the formula:

v0 = d / t

Substituting the given values, we get:
v0 = 120 m / 5.1 s = 23.53 m/s

Step 2: Calculate the final velocity (v) when the car comes to a stop.
We can use the following equation to find the final velocity:

v = v0 + at

Since the car comes to a stop, the final velocity (v) is 0. We can substitute the values into the equation and solve for acceleration (a):

0 = 23.53 m/s + a * 4.0 s

Rearranging the equation, we get:
a = -23.53 m/s / 4.0 s
a = -5.88 m/s^2

Step 3: Convert the acceleration to g's.
To express the answer in terms of g's, divide the acceleration (a) by the acceleration due to gravity (g):

a_g = a / g

Substituting the values, we get:
a_g = -5.88 m/s^2 / 9.80 m/s^2
a_g = -0.6 g's

Therefore, the acceleration of the sports car is approximately -0.6 g's.

a car moving constants speed travels 150 m in .8.0 s. it then brakes and comes to a stop after 5.0. Determine its deceleration

part a. 5.88 m/s^2

part b. .6g