# math

There are 9 more quarter then dimes.if the total value of the coins is 6.8, how ,any quarters are there?

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1. Is the total value \$6.80?

If so, then let Q be the number of quarters and D be the number of dimes.

You know that
Q -D = 9, and
0.25Q + 0.1D = 6.80
Solving bu substitution,
0.25Q + 0.1(Q-9) = 6.80
0.35Q = 7.70
Q = 22
Now solve for D

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posted by drwls
2. omg ty u are a super pro

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3. ty, yw :)

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posted by drwls

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