math

There are 9 more quarter then dimes.if the total value of the coins is 6.8, how ,any quarters are there?

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  1. Is the total value $6.80?

    If so, then let Q be the number of quarters and D be the number of dimes.

    You know that
    Q -D = 9, and
    0.25Q + 0.1D = 6.80
    Solving bu substitution,
    0.25Q + 0.1(Q-9) = 6.80
    0.35Q = 7.70
    Q = 22
    Now solve for D

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    posted by drwls
  2. omg ty u are a super pro

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  3. ty, yw :)

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    posted by drwls

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