A person with skin area 2 m2 and 0.97 radiation efficiency is at rest and has a skin temperature of 28 C in an environment with a uniform temperature of 22 C

.Calculate the heat loss rate in watts

To calculate the heat loss rate in watts, we need to use the formula for heat loss through radiation, known as the Stefan-Boltzmann Law.

The formula for heat loss through radiation is:

Q = εσA(T1^4 - T2^4)

Where:
Q = Heat loss rate
ε = Radiation efficiency (given as 0.97)
σ = Stefan-Boltzmann constant (5.67 × 10^-8 W/m^2K^4)
A = Surface area of the skin (given as 2 m^2)
T1 = Skin temperature (given as 28°C, which needs to be converted to Kelvin)
T2 = Temperature of the environment (given as 22°C, which also needs to be converted to Kelvin)

First, let's convert the temperatures from Celsius to Kelvin:

T1(K) = T1(C) + 273.15
T1(K) = 28 + 273.15
T1(K) = 301.15 K

T2(K) = T2(C) + 273.15
T2(K) = 22 + 273.15
T2(K) = 295.15 K

Now we can plug the values into the formula:

Q = 0.97 × 5.67 × 10^-8 × 2 × (301.15^4 - 295.15^4)

Calculating this equation will give us the heat loss rate in watts.