A car travels directly northwards at 10m/s.it then accelarates at 2m/s^2 over a distance of 200m.calculate the car's velocity after 200m.
Vfinal^2/2 - Vo^2/2 = a*X
X = 200 m; a = 2 m/s^2; Vo = 10 m/s
Solve for Vfinal
And for full marks don't forget to add the direction.
To calculate the car's velocity after 200m, we need to consider the initial velocity and the acceleration.
Given:
Initial velocity (u) = 10 m/s
Acceleration (a) = 2 m/s^2
Distance (s) = 200 m
We can use the equation of motion:
v^2 = u^2 + 2as
where:
v = final velocity
Rearranging the equation to solve for v, we have:
v^2 = u^2 + 2as
v^2 = (10 m/s)^2 + 2 (2 m/s^2)(200 m)
v^2 = 100 m^2/s^2 + 800 m^2/s^2
v^2 = 900 m^2/s^2
v = √900 m/s
v = 30 m/s
Therefore, the car's velocity after 200m is 30 m/s.