A certain sports car accelerates from 0 to 60 mph in 9.0 s (average acceleration = 3.0
m/s2). The mass of the car is 1354 kg. The average backward force due to air drag during
acceleration is 280 N. Find the forward force required to give the car this acceleration.
F(fwd) - F(bkwd) = M a
Based upon the speed change in 9.0 s, a is actually 2.98 m/s^2, not 3.0. I will use 3.0 anyway. They gave you more information that you need.
Solve for F(fwd)
F(fwd) = 280 + (1354)*(3.0) N
according to newton's second law;it states that
F=ma
therfore,F(force of car)-F(force of airdrag)=ma
ie:F-F=Ma
inorder to find the "F" transpond one F from left hand side to right hand side.
therfore,F=F+MA
ie:F=280+(1354)x(3.0)
F=4902.
Therfore the force needed to give the car this accelaration=4902.
my teacher book is the answer is 4.4e3
Why did the sports car go to therapy?
Because it had a lot of unresolved "drag" issues!
But let's try to solve this seriously amidst all the horsepower jokes. To find the forward force required, we need to consider the net force acting on the car.
The net force is given by the equation F_net = F_forward - F_drag, where F_forward is the forward force and F_drag is the backward force due to air drag.
Now, we know that mass (m) multiplied by acceleration (a) gives the net force (F_net). Rearranging, we get F_net = m * a.
So, F_forward - F_drag = m * a
Substituting the values given, we get F_forward - 280 N = 1354 kg * 3.0 m/s^2
Now, let's solve for F_forward!
F_forward = (1354 kg * 3.0 m/s^2) + 280 N
Calculating that out will give you the forward force required to give the car this acceleration.
To find the forward force required to give the car the specified acceleration, we need to consider the forces acting on the car during acceleration. The net force acting on the car is given by the equation:
Net Force = Mass * Acceleration
In this case, the given average acceleration is 3.0 m/s^2, and the mass of the car is 1354 kg. By substituting these values into the equation, we can calculate the net force acting on the car:
Net Force = 1354 kg * 3.0 m/s^2 = 4062 N
Now, we need to consider the effect of air drag on the car during acceleration. The question states that the average backward force due to air drag is 280 N. Since this force is acting in the opposite direction of the acceleration, we can subtract it from the net force to find the forward force required:
Forward Force = Net Force - Air Drag Force
Forward Force = 4062 N - 280 N
Forward Force = 3782 N
Therefore, the forward force required to give the car the specified acceleration is 3782 N.