Please help me
One bowling charges $5.50 for shoe rental plus $2.50 per game. A second bowling alley charges $4.00 for shoe rental plus $3.00 per game. If one person rents a pair of shoes to bowl, how many games should they bowl to make the first bowling alley cheaper than the second bowling alley.
First bowling alley:
1 game = $8.00
2 games = 10.50
3 games = 13.00
Second alley:
1 game = 7.00
2 games = 10.00
3 games = 13.00
Take it from there.
Monica needs a moving truck. Company A charges $40 per day and company B charges a $60 fee plus $20 per day. For what number of days in the cost the same?
To determine how many games one person should bowl to make the first bowling alley cheaper than the second, we need to compare the total cost for each bowling alley.
For the first bowling alley, the cost consists of $5.50 for shoe rental and $2.50 per game.
For the second bowling alley, the cost consists of $4.00 for shoe rental and $3.00 per game.
Let's set up an equation to compare the costs of both bowling alleys:
Cost of First Bowling Alley = Cost of Second Bowling Alley
$5.50 + $2.50x = $4.00 + $3.00x
Where x represents the number of games.
To solve this equation, we can simplify it:
$5.50 - $4.00 = $3.00x - $2.50x
$1.50 = $0.50x
Now we can solve for x:
x = $1.50 / $0.50
x = 3
Therefore, if one person rents a pair of shoes to bowl, they should bowl at least 3 games for the first bowling alley to be cheaper than the second bowling alley.
To determine how many games a person should bowl for the first bowling alley to become cheaper than the second bowling alley, we can compare the costs of both options.
Let's denote:
Cost of shoe rental at the first alley: $5.50
Cost per game at the first alley: $2.50
Cost of shoe rental at the second alley: $4.00
Cost per game at the second alley: $3.00
To find the number of games where the first alley becomes cheaper, we need to set up an equation.
Let's assume the number of games played is 'x'.
For the first bowling alley, the cost would be:
Cost = Shoe rental cost + (Game cost per game * Number of games)
Cost = $5.50 + ($2.50 * x)
Cost = $5.50 + $2.50x
For the second bowling alley, the cost would be:
Cost = Shoe rental cost + (Game cost per game * Number of games)
Cost = $4.00 + ($3.00 * x)
Cost = $4.00 + $3.00x
To find the point where the first alley becomes cheaper than the second alley, we set up the equation:
$5.50 + $2.50x < $4.00 + $3.00x
Now we can solve for 'x':
$5.50 - $4.00 < $3.00x - $2.50x
$1.50 < $0.50x
Dividing both sides of the inequality by $0.50:
$1.50 / $0.50 < x
3 < x
Therefore, the person should bowl more than three games for the first bowling alley to become cheaper than the second bowling alley.