The latent heat of fusion of water is 3.34 x 105 J/kg. A farmer places a barrel containing 1000 kg of water in his barn one winter's night. When the water cools to 0oC, it begin to freeze. How much heat does the water give out while it is freezing until it has all become ice at 0oC?
Question 5 options:
A) 3.34 x 10^8 J
B) 3.34 x 10^3 J
C) 3.34 x 10^6 J
D) 3.34 x 10^4 J
heat=mass*heatfusion=1E3 * 3.34E5
so what is the answer?
Q= mass x latent heat of fusion
Q= 1000x1000x3.3x100000
Q=3.34x10⁸
To find the amount of heat the water gives out while it is freezing, we need to calculate the heat transfer during the phase change from liquid to ice.
The formula to calculate the heat transfer during a phase change is:
Q = m * L
Where:
Q is the amount of heat transferred
m is the mass of the substance undergoing the phase change
L is the latent heat of fusion
Given that the mass of water is 1000 kg and the latent heat of fusion is 3.34 x 10^5 J/kg, we can substitute these values into the formula:
Q = 1000 kg * 3.34 x 10^5 J/kg
Now, we can calculate the answer:
Q = 3.34 x 10^8 J
Therefore, the amount of heat the water gives out while it is freezing until it has all become ice at 0°C is 3.34 x 10^8 J.
So, the correct answer is:
A) 3.34 x 10^8 J