# calculus

what is the derivative of y = (4x squared - 5/2x+3)raise to 3/2 three halves..

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1. Use the "chain rule"
dy/dx = (dy/du)*(du/dx)
with u(x) = 4x^2 -5/2 x + 3

dy/dx = (3/2)*(4x^2 -5/2 x +3)^1/2 * (8x - 5/2)

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posted by drwls

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