A runner moving at a velocity of 6 m/s increases the velocity in a 2 s time

interval to a rate of 10 m/s. What is the rate of acceleration?

a = (Vf-Vo) / t = (10-6) / 2 = 2m/s^2.

Well, clearly this runner is in a hurry to get somewhere! Let's crunch some numbers. We know that the initial velocity is 6 m/s and the final velocity is 10 m/s. To find the rate of acceleration, we can use the formula:

Acceleration = (change in velocity) / (change in time)

The change in velocity is the final velocity minus the initial velocity, which is 10 m/s - 6 m/s = 4 m/s. The change in time is given as 2 seconds.

So, plugging these values into the formula:

Acceleration = 4 m/s / 2 s = 2 m/s²

Voila! The rate of acceleration is 2 m/s². I hope this answer didn't put you in a sprint!

To find the rate of acceleration, we can use the formula:

Acceleration (a) = Change in Velocity (Δv) / Time (Δt)

Given that the initial velocity (u) is 6 m/s, the final velocity (v) is 10 m/s, and the time interval (Δt) is 2 s, we can calculate the change in velocity (Δv):

Δv = v - u
Δv = 10 m/s - 6 m/s
Δv = 4 m/s

Now we can substitute the values into the formula to find the acceleration:

a = Δv / Δt
a = 4 m/s / 2 s
a = 2 m/s²

Therefore, the rate of acceleration is 2 m/s².

To find the rate of acceleration, we can use the formula:

Acceleration (a) = Change in velocity (Δv) / Time interval (Δt)

In this case, the initial velocity (u) of the runner is 6 m/s, and after 2 seconds, the velocity (v) increases to 10 m/s. Therefore, the change in velocity (Δv) is:

Δv = v - u = 10 m/s - 6 m/s = 4 m/s

The time interval (Δt) is given as 2 seconds.

Now we can substitute these values into the formula to find the rate of acceleration:

Acceleration (a) = Δv / Δt = 4 m/s / 2 s = 2 m/s²

Therefore, the rate of acceleration is 2 m/s².