a cube with 2-inch sides is placed on a cube with 3-inch sides. Then a cube with 1-inch sides is placed on the 2-inch cube. What is the surface area of the three cubes?
i have been these are the only ones that i have problems with because i forgot how to do it nevermind then
To find the surface area of each cube, we need to calculate the sum of the areas of all six faces of each cube.
First, let's find the surface area of the 2-inch cube:
Since all sides of the cube have a length of 2 inches, the area of each face is 2 * 2 = 4 square inches. Since there are six faces in total, we need to multiply the area of one face by 6 to find the total surface area.
So, the surface area of the 2-inch cube is 4 * 6 = 24 square inches.
Next, let's find the surface area of the 3-inch cube:
Since all sides of the cube have a length of 3 inches, the area of each face is 3 * 3 = 9 square inches. Multiplying the area of one face by 6 gives us the total surface area.
Therefore, the surface area of the 3-inch cube is 9 * 6 = 54 square inches.
Lastly, let's find the surface area of the 1-inch cube:
Since all sides of the cube have a length of 1 inch, the area of each face is 1 * 1 = 1 square inch. By multiplying the area of one face by 6, we can determine the total surface area.
Thus, the surface area of the 1-inch cube is 1 * 6 = 6 square inches.
To find the total surface area of all three cubes, we add up the surface areas of each cube:
24 square inches + 54 square inches + 6 square inches = 84 square inches.
Therefore, the total surface area of the three cubes is 84 square inches.
4+5=9
Christina -- you seem to be using Jiskha as a dumping ground for your homework.
I won't help you with any more problems until you show some effort.