A classroom measures 32ft long, 25ft wide, and 9ft high. The combined area of doors and window is 140 ft^2. What is the remaining area of the four walls of the room?
886 sp. ft.
its really easy... just find the area of all the wall except for the floor and ceiling. and subtract that by 140ft
If all of the following operations are present in math calculation which of them should always be done first??
140
To find the remaining area of the four walls of the room, we need to calculate the total area of all the walls and subtract the area of the doors and windows.
First, let's calculate the area of each wall. Since the room has four walls, two of the walls are opposite each other and have the same dimensions, while the other two walls (front and back) also have the same dimensions.
The dimensions of the room are as follows:
Length (L) = 32 ft
Width (W) = 25 ft
Height (H) = 9 ft
The area of each long wall (length x height) is:
Long Wall Area = L x H = 32 ft x 9 ft = 288 ft^2
The area of each short wall (width x height) is:
Short Wall Area = W x H = 25 ft x 9 ft = 225 ft^2
Now, let's calculate the total area of all four walls:
Total Wall Area = 2 x (Long Wall Area + Short Wall Area)
Total Wall Area = 2 x (288 ft^2 + 225 ft^2)
Total Wall Area = 2 x 513 ft^2
Total Wall Area = 1026 ft^2
Next, we need to subtract the area of the doors and windows, which is given as 140 ft^2:
Remaining Wall Area = Total Wall Area - Area of Doors and Windows
Remaining Wall Area = 1026 ft^2 - 140 ft^2
Remaining Wall Area = 886 ft^2
Therefore, the remaining area of the four walls of the room is 886 ft^2.
Total WALL area is
2(32x9) + 2(25x9) - 140 ft^2.
Do the calculation.
Floor and ceiling areas are not included.