Find the area of the parallelogram with vertices at...? (-6,-4), (0,-4), (3,4), and (-3,4)

A) 14
B) 48
C) 24
D)
PLEASE HELP A.S.A.P., beggers can't be choosers but maybe an explanation?

Procedure: Calculate 1 hor side and the height. A = bh.

A(-6,-4), D(0,-4). AD is a hor. side.
AD = 0-(-6) = 6.

A(-6,-4), B(-3,4). AB is a slant line.
tanA = Y/X = (4-(-4)) / (-3-(-6) = 8/3.
Y = 8 = h.

Area = bh = 6 * 8 = 48.

To find the area of a parallelogram, we can use the formula: Area = base * height. However, in order to calculate the base and height, we need to first determine two adjacent sides of the parallelogram.

In this case, we can choose any two adjacent vertices to find the sides. Let's use the first two vertices (-6,-4) and (0,-4) to find the base of the parallelogram.

The distance formula between two points (x1, y1) and (x2, y2) is given by:

Distance = √((x2 - x1)^2 + (y2 - y1)^2)

So, let's calculate the distance between (-6,-4) and (0,-4):

Distance = √((0 - (-6))^2 + (-4 - (-4))^2)
= √((0 + 6)^2 + (0)^2)
= √(6^2 + 0^2)
= √(36)
= 6

Therefore, the base of the parallelogram is 6.

Now, let's find the height of the parallelogram using the same formula with the second and third vertices (0,-4) and (3,4):

Distance = √((3 - 0)^2 + (4 - (-4))^2)
= √((3)^2 + (8)^2)
= √(9 + 64)
= √(73)

Therefore, the height of the parallelogram is √(73).

Now that we have the base (6) and the height (√(73)), we can calculate the area using the formula:

Area = base * height
= 6 * √(73)
≈ 24.22

Since the answer choices are given as integers, we need to round our answer to the nearest integer.

Therefore, the nearest integer to 24.22 is 24.

Therefore, the area of the parallelogram is approximately 24.

The correct answer is C) 24.