A car starts from rest and accelerates for 6.1 s
with an acceleration of 3.1 m/s2.
How far does it travel?
Answer in units of m.
To find the distance traveled by the car, we can use the following formula:
distance = (initial velocity * time) + (0.5 * acceleration * time^2)
Given that the car starts from rest, its initial velocity is 0 m/s. The acceleration is given as 3.1 m/s^2, and the time taken is 6.1 seconds.
Plugging these values into the formula, we get:
distance = (0 * 6.1) + (0.5 * 3.1 * (6.1)^2)
Simplifying the equation further:
distance = 0 + (0.5 * 3.1 * 37.21)
Calculating the value inside the parentheses:
distance = 0 + (1.55 * 37.21)
Finally, calculating the product:
distance = 57.6055
Therefore, the car travels approximately 57.61 meters.
X = (a/2) t^2
a = 3.1 m/s^2
t = 6.1 s
X = 57.7 m