A diver descent 100 m below sea level. If the density of sea water is 1024 kg m-3, find the pressure she will experience.
At depth x (meters),
P(x) = Po + (density)*g*x
Po is atmospheric pressure at sea level, which is typically 1.013*10^5 N/m^2.
g = 9.81 m/s^2 is the acceleration of gravity
Density = 1024 kg/m^2
Your answer, in units of N/m^2, should be equal to about 11 Po