How do I solve 7x=3x+48
do 7x-3x= 4x
divide: 48/4
x=12
Thanks!
To solve the equation 7x = 3x + 48, you need to isolate the variable "x" on one side of the equation. Here's how you can do it step by step:
Step 1: Simplify both sides of the equation by combining like terms. On the right side, there are no like terms, so it remains as 3x + 48. On the left side, there is only one term, which is 7x. So, the equation becomes: 7x = 3x + 48.
Step 2: To isolate x on one side, you need to get rid of the 3x on the right side. You can do this by subtracting 3x from both sides of the equation. This results in: 7x - 3x = 3x - 3x + 48. Simplifying this further, 7x - 3x becomes 4x, so the equation now becomes: 4x = 48.
Step 3: Now, you need to isolate x by itself. Since 4x means 4 times x, you can cancel out the multiplication by dividing both sides of the equation by 4. This gives you: (4x)/4 = 48/4. Simplifying further, 4x/4 becomes x, so the equation is now: x = 12.
Therefore, the solution to the equation 7x = 3x + 48 is x = 12.