An apple of mass 0.1kg is thrown from a 123 meter high building at an angle of 45 degrees with an initial velocity of 5. How long does it take for the apple to hit the ground? (assume g = 9.8 m.s-2)
What are the units of velocity? m/s?
5 m/s is a very slow velocity for a thrown object. It's about 11 miles an hour.
Solve this equation for y = 0 altitude above ground:
y = Vo sin 45 t - (g/2) t^2 + 123
= 3.5455 t - 4.9 t^2 + 123 = 0
Take the positive-root answer to this quadratic equation
OR
Add the time it takes to reach maximum height (0.361 s), and the time it takes to hit the ground from there. You will need to calculate the maximum height to do it this way. That will be 123 + 2.13 m