'm'gms of carbon reacts completely with 'n'gms of oxygen to produce carbon-dioxide.The mass of oxygen required to react with 'm'gms of carbon completely and produce carbon-monoxide is
Not entirely sure what is needed here
Start from the equations
C + O2 -> CO2
1 mole + 1 mole -> 1 mole
so
m/12 + n/32 produces CO2
so m/12=n/32 or
32m=12n
8m=3n
n=8m/3
C + 1/2O2 -> CO
1 mole + 1/2 mole -> 1 mole
m/12 n/32
in this case
m/12= 2n/32
m/12=n/16
mass of O2 required is
16m/12 or 4m/3
which is what we expect as half the number of moles i.e. half the mass i needed.
To determine the mass of oxygen required to react with 'm' grams of carbon completely and produce carbon monoxide, we need to calculate the ratio of the molar masses and stoichiometric coefficients involved in the reactions.
Let's start by comparing the reactions:
1. Carbon + Oxygen -> Carbon Dioxide
2. Carbon + Oxygen -> Carbon Monoxide
First, we need to determine the molar masses of carbon dioxide (CO2) and carbon monoxide (CO).
The molar mass of carbon dioxide (CO2) = 12.01 g/mol (atomic mass of carbon) + 2*(16.00 g/mol) (atomic mass of oxygen)
= 12.01 g/mol + 32.00 g/mol
= 44.01 g/mol
The molar mass of carbon monoxide (CO) = 12.01 g/mol (atomic mass of carbon) + 16.00 g/mol (atomic mass of oxygen)
= 28.01 g/mol
Next, let's determine the stoichiometric coefficients of the reactions. The balanced chemical equations are:
1. Carbon + Oxygen -> Carbon Dioxide
C + O2 -> CO2
The stoichiometric coefficient (ratio) between carbon and oxygen in this reaction is 1:2.
2. Carbon + Oxygen -> Carbon Monoxide
C + O2 -> CO
The stoichiometric coefficient (ratio) between carbon and oxygen in this reaction is 1:1.
Now, let's use the concept of equivalent masses to find the mass of oxygen required to react with 'm' grams of carbon completely.
For the first reaction (to produce carbon dioxide):
The equivalent mass of oxygen in this reaction is the molar mass of oxygen (32.00 g/mol) divided by the stoichiometric coefficient of oxygen (2).
Equivalent mass of oxygen in reaction 1 = 32.00 g/mol / 2 = 16.00 g/mol
For the second reaction (to produce carbon monoxide):
The equivalent mass of oxygen in this reaction is the molar mass of oxygen (16.00 g/mol) divided by the stoichiometric coefficient of oxygen (1).
Equivalent mass of oxygen in reaction 2 = 16.00 g/mol / 1 = 16.00 g/mol
Therefore, the mass of oxygen required to react with 'm' grams of carbon completely and produce carbon monoxide is the same as the equivalent mass of oxygen in reaction 2, which is 16.00 g/mol.
Note: The equivalent mass is the mass of a substance that combines with or replaces one mole or gram equivalent of another substance in a reaction.