# physics

The acceleration due to gravity on the moon is 1.62 m/s2. What is the length of a pendulum whose period on the moon matches the period of a 4.50-m-long pendulum on earth

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1. T^2 = 4(pi)^2 * (L/g).

L2 = (g2/g1)L1 = (1.62/9.8)4.5=0.74m.

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posted by Henry

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