math.

A theater purchases $500 worth of Sticky Bears and chocolate bombs. Each bag of Sticky Bears costs $1.50 and each bag of Chocolate Bombs costs $1.00. If a total of 400 bags of candy were purchased, how many bags of Chocolate Bombs did the theater buy?

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  1. Let
    S=number of bags of sticky bears, then
    400-S=number of bags of chocolate bombs.

    From total cost = $500, we get
    1.5S+1.0(400-S)=500
    Solve for S
    0.5S = 500-400
    S=200

    Quick way:
    each bag of sticky bears costs 1.50
    each bag of chocolate costs 1.00
    Average cost = $500/400=1.25
    which is smack in between 1.00 and 1.50.
    So equal number of bags of each, namely 200.

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    posted by MathMate

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