A BLOCK OF MASS 20KG MOVING WITH A SPEED OF 18 KM/H EXPLODES AND SPLITS INTO 2 PARTS.ONE PART OF MASS 15 KG COMES TO REST FIND THE VELOCITY OF SECOND PART?
20 * 18 = 15 * 0 + 5 * v
because
momentum before = momentum after
since there are no external forces on the system to change its momentum
20*18=15*0+(20-15)*x
360=0+5*x
x=360/5
velocity of the other part=72
To find the velocity of the second part, we can use the principle of conservation of momentum. According to this principle, the total momentum before the explosion should be equal to the total momentum after the explosion.
First, let's convert the speed of the block from km/h to m/s. We know that 1 km/h is equal to 0.2778 m/s. So, the initial speed of the block is:
18 km/h * 0.2778 m/s = 5 m/s
The total momentum before the explosion can be calculated as the product of the mass and velocity of the block:
Initial momentum = mass * initial velocity
= 20 kg * 5 m/s
= 100 kg·m/s
After the explosion, one part of the block with a mass of 15 kg comes to rest. This means its velocity becomes zero. Let's call the velocity of the second part "v2".
The total momentum after the explosion can be expressed as the sum of the momentum of the first part (which is now at rest) and the momentum of the second part:
Final momentum = (mass of first part * velocity of first part) + (mass of second part * velocity of second part)
= (15 kg * 0 m/s) + (mass of second part * v2)
= 0 + (mass of second part * v2)
Since the total momentum before and after the explosion should be equal, we can set up an equation:
Initial momentum = Final momentum
100 kg·m/s = 0 + (mass of second part * v2)
Now, we can solve for "v2":
v2 = (100 kg·m/s) / (mass of second part)
Given that the mass of the second part is not provided in the question, we cannot determine the exact velocity of the second part without that information. However, if the mass of the second part is provided, you can substitute that value into the equation to find the velocity (v2).