# MATH 157

How do I determine the real number solution for the following problem: The problem reads : Determine the number of real-number solutions to the equation from the given graph. x^2 - x + 15 = 0, given the graph of y = x^2 - x + 15

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1. For any quadratic of the form
ax^2 + bx + c = 0 , evaluate b^2 - 4ac

if b^2 - 4ac > 0 , there will be 2 distinct real roots
if b^2 - 4ac < 0 there will be 2 complex roots
if b^2 - 4ac = 0 there will be one real roots, (actually two equal roots)

b^2 - 4ac = 1 - 4(1)(15) = -59

So there are no real roots.

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posted by Reiny
2. ty

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posted by Janelle

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