Evaluate 5C3
Is it 5C^3? Is 3 an exponent?
its like 5^C3....i posted it on wednesday and Reiny responded but never answered me back....
its the counting principle....
Do you mean combinations of five taken 3 at a time perhaps?
If so
C(n,r) = n!/[r!(n-r)! ]
= 5!/[3!2!]
=5*4/2!
=5*2
=10
yes, thank you Damon...i couldn't figure how to explain it
To evaluate 5C3, we need to apply the formula for combinations.
The formula for combinations is given as:
nCr = n! / (r! * (n - r)!)
where n is the total number of items and r is the number of items to be selected.
In this case, we want to find the value of 5C3, which means we have 5 items available and we want to select 3 of them.
Using the formula, we can calculate 5C3 as:
5C3 = 5! / (3! * (5 - 3)!)
First, let's calculate the factorials:
5! = 5 * 4 * 3 * 2 * 1 = 120
3! = 3 * 2 * 1 = 6
(5 - 3)! = 2! = 2 * 1 = 2
Now, substitute the calculated factorials into the formula:
5C3 = 120 / (6 * 2)
Dividing the numerator by the denominator:
5C3 = 120 / 12
Resulting in:
5C3 = 10
Therefore, 5C3 is equal to 10.