Mathematics Calculus
How do I solve 3xy^3dy/dx=y^2x^2+5x^3y+y^4
Let u=y/x, then y=u*x and y'=u'*x+u
We have the equation:
3x(u*x)^3(u'x+u)=(u*x)^2x^2+5x^3(u*x)+
+(u*x)^4
Divide on u*x^4
3u^2(u'x+u)=u+5+u^3
u'x+u=(u^3+u+5)/3u^2
u'x=(-2u^3+u+5)/3u^2
3u^2du/(-2u^3+u+5)=dx/x (u'=du/dx)
You can ask a new question or answer this question .
Similar Questions
Top answer:
To solve the given differential equation, 3xy^3(dy/dx) = y^2x^2 + 5x^3y + y^4, we need to separate
Read more.
Top answer:
To simplify 6xy(3xy)^-2, we need to apply the exponent to the term inside the parentheses first. The
Read more.
Top answer:
1. Correct, assuming it is 2/(3xy) 2. Correct, assuming it is 3x³y/(2z³)
Read more.
I have to simplify (-x^5y^4)^4(3x^2y)^2(1/3xy) I did (x^20y^16)(9x^4y^2)(1/3xy) (9x^24y^18)(1/3xy) 3x^25y^19 Is this correct?
Top answer:
First of all, it's not a polynomial,as there is only one term. It's ok to here: (9x^24y^18)(1/3xy)
Read more.
7y^4+x^3y+x=4 using implicit differentation, how do i solve this problem. it is a textbook example but the partwhere i "use the
Top answer:
I get 28y^3(dy/dx) + x^3(dy/dx) + y(3x^2) + 1 = 0 dy/dx(28y^3 + x^3) = - 1 - 3(x^2)(y) dy/dx = (- 1
Read more.
X+y+z=1......(1) x^2+y^2+z^2=35........(2) x^3+y^3+z^3=97.........(3) solution but from 3 (x^3+y^3)=(x+y)^3-3xy(x+y)......(4)
Top answer:
Aside from the typos in (4) you are ok. 4) 3xy' + 5y' - 3cos(2x+3y)y' = 2 cos (2x + 3y) - 3y 5)
Read more.
Top answer:
12 x^-2 y^4 /{ -3 x (y^-7) } ?? is -4 x^-3 y^11 = -4 y^11/x^3
Read more.
Top answer:
actually in the end of both formulas its y^3 sorry....
Read more.