Jane has only $1 and $5 in her wallet, and they total $79.00. If she has a total of 23 bills, how many of each bill does she have?
Let x = $1 bills.
Let y = $5 bills
x + 5y = 79
x = 79 - 5y
x + y = 23
79 - 5y + y = 23
79 - 23 = 4y
56 = 4y
14 = y
Thank you Ms. Sue
You're welcome, Mark.
To solve this problem, we can set up a system of equations based on the given information.
Let's say Jane has x bills of $1 and y bills of $5.
We are given two pieces of information:
1. The total value of the bills is $79.00:
$1(x) + $5(y) = $79.00 ----(equation 1)
2. The total number of bills is 23:
x + y = 23 ----(equation 2)
Now, we have a system of two equations with two unknowns. We can solve this system to find the values of x and y.
First, let's rearrange equation 2 to express x in terms of y:
x = 23 - y ----(equation 3)
Substituting equation 3 into equation 1, we can solve for y:
$1(23 - y) + $5(y) = $79.00
Simplifying this equation:
$23 - $1y + $5y = $79.00
$4y = $79.00 - $23.00
$4y = $56.00
Dividing both sides by $4, we find:
y = $56.00 / $4
y = 14
Now that we have the value of y, we can substitute it back into equation 3 to find x:
x = 23 - y
x = 23 - 14
x = 9
Therefore, Jane has 9 bills of $1 and 14 bills of $5 in her wallet.