Math

find a quadratic equation having 3+root3 and 3-root3

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  1. have you learned the sum and product property of quadratics? If so , this is easy
    sum = 3+√3 + 3-√3 = 6
    product = (3+√3)(3-√3) = 9 - 3 = 6

    equation: x^2 - 6x + 6 = 0

    if not ...

    expand
    (x - (3+√3))(x - (3-√3))= 0
    you will get the same answer as above

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    posted by Reiny

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