find a quadratic equation having 3+root3 and 3-root3

have you learned the sum and product property of quadratics? If so , this is easy

sum = 3+√3 + 3-√3 = 6
product = (3+√3)(3-√3) = 9 - 3 = 6

equation: x^2 - 6x + 6 = 0

if not ...

expand
(x - (3+√3))(x - (3-√3))= 0
you will get the same answer as above