If mean of 1, 2, 3, --------- n is 6n/11, then n is
To find the value of n, we can use the formula for the sum of an arithmetic series:
Sn = (n/2)(a + L)
where Sn is the sum of the series, n is the number of terms, a is the first term, and L is the last term.
In this case, we know that the mean of the series is 6n/11. The mean of an arithmetic series is equal to the sum of all the terms divided by the number of terms:
mean = sum/n
So we can write the equation:
6n/11 = (n/2)(1 + L)
Simplifying this equation further:
12n = 11n + 11L
Rearranging terms:
L = n
Now we substitute this value of L in the equation:
12n = 11n + 11n
12n = 22n
n = 0
Therefore, n is equal to 0.